RHSLilSweetie07
New member
- Joined
- Sep 25, 2005
- Messages
- 25
The problem is as follows:
[(x*2y^-1*z^-2)/(x*y^3*z^-4)]^-3
The first thing I did was flip the fraction and made the outer exponent positive. Then I cubed every term in the fraction to get the following:
(x^3*y^9*z^-12)/(x^3*8y^-3*z^-6)
Have I done everything right so far?
From there on out, I canceled out the x's and made the negative exponents positive:
(8*y^12*z^6)/(z^12).
My answer was (8*y^12)/(z^6), but my teacher told me it was wrong. Please help me realize where I messed up.
[(x*2y^-1*z^-2)/(x*y^3*z^-4)]^-3
The first thing I did was flip the fraction and made the outer exponent positive. Then I cubed every term in the fraction to get the following:
(x^3*y^9*z^-12)/(x^3*8y^-3*z^-6)
Have I done everything right so far?
From there on out, I canceled out the x's and made the negative exponents positive:
(8*y^12*z^6)/(z^12).
My answer was (8*y^12)/(z^6), but my teacher told me it was wrong. Please help me realize where I messed up.