need help now

[gracierox77]

In the pythagoras theorem, if the formula is
a^2+b^2=c^2,

How do you do it if a=1/3 and b=2/3?

 

[dagr8est]

In the pythagoras theorem, if the formula is
a^2+b^2=c^2,

How do you do it if a=1/3 and b=2/3?

In general, (x/y)^z = (x^z)/(y^z) where y cannot be 0.

So in your case, (1/3)^2=(1^2)/(3^2)=1/9 and (2/3)^2=(2^2)/(3^2)=4/9.

Solve for c and you should get +/-sqrt(5)/3. If you are applying this to an actual triangle, you can ignore the negative possibility.