I NEED TO FIND THE VALUE OF x WHEN y = 0 y = 1/2(x-4)^2-3
N notsure New member Joined Feb 12, 2006 Messages 9 Mar 9, 2006 #1 I NEED TO FIND THE VALUE OF x WHEN y = 0 y = 1/2(x-4)^2-3
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Mar 9, 2006 #2 notsure said: I NEED TO FIND THE VALUE OF x WHEN y = 0 y = 1/2(x-4)^2-3 Click to expand... Substitute 0 for y: 0 = (1/2)(x - 4)<SUP>2</SUP> - 3 Add 3 to both sides: 3 = (1/2)(x - 4)<SUP>2</SUP> Multiply both sides by 2: 6 = (x - 4)<SUP>2</SUP> Take the square root of both sides: ± √6 = x - 4 Ok...you finish it.
notsure said: I NEED TO FIND THE VALUE OF x WHEN y = 0 y = 1/2(x-4)^2-3 Click to expand... Substitute 0 for y: 0 = (1/2)(x - 4)<SUP>2</SUP> - 3 Add 3 to both sides: 3 = (1/2)(x - 4)<SUP>2</SUP> Multiply both sides by 2: 6 = (x - 4)<SUP>2</SUP> Take the square root of both sides: ± √6 = x - 4 Ok...you finish it.
