Need help in solving a word problem

A

aruss

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Aug 24, 2010
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I'm having trouble setting up the following problem, can you help me please?

Anne has $5000 to invest. She invests some at 7% and 6%. After 1 year she has $332 in interest. How much did she invest in each percent?

I've tried 5000(7)(.01 + 5000(6)(.01) = 332 This doesn't seem to get me to where I need to be to solve the problem.
 


Where is your variable ?

Let x = amount invested at 7%

Then 5000 - x = the amount invested at 6%

The interest from 7% is 0.07x and the interest from 6% is 0.06(5000 - x).

These two interest amounts add up to 332. Write an equation, and solve for x.

 
Thank you - however I'm still confused as far as writing an equation to solve for x. Will it look something like this:

5000 -332 x .06 = x
 


The interest from the 7% investment [0.07x] PLUS the interest from the 6% investment [0.06(5000 - x)] EQUALS the total interest [332]

 
Ok, here's my problem I see what you're doing i don't know how to write the equation to solve for x.

I've tried 5000/.07 + 5000/.06 = 332 doesn't give me a number that I can plug in for x.
I've tried 5000 x .07 = 350

.06(5000 - 350) = 332
.06(4650) = 332
279 = 332

I'm not getting how to solve for x....sorry about being slow, I'm just not getting it.
 


Do you understand the given scenario ?

Monies are invested at two different rates. This means two different amounts of interest will be earned. We are told that their total is $332.

I told you how much interest is earned at 7%.

I told you how much interest is earned at 6%.

I told you to ADD these two amounts together because together they EQUAL the total interest.

That is your equation ! 8-)

0.07x + 0.06(5000 - x) = 332

 
Yes, I understand that the monies are invested at two different rates, and i tried solving it this way

.07 x 5000 = x
I got 3500 = x

i then took 3500 x .07 = 245
i then ran .06 x 1500 = 90

90 + 245 = 335 NOT 332 I don't see where my mistake is...in playing around with the problem 3200 invested at 7% = 224 and 1800 @ 6% = 108 which total 332.
My problem is how do I find the 3200? If you gave me that answer I missed it. I'm just trying to learn how to solve for x....there's something that I'm missing, and that's all I need to know.
 


When we solve the equation above for x, we know how much money was invested at 7%.

After all, we decided at the very beginning to let the symbol x represent the amount invested at 7%.

Once we know the value of x (by solving the equation), we simply subtract that amount from 5000, to find the amount invested at 6%.

Again, here is the equation that shows the sum of the two interest earnings which total $332.

0.07x + 0.06(5000 - x) = 332

Now, we solve this equation for x. In other words, we perform algebraic steps to rearrange the equation into the form:

x = something

To begin, use the Distributive Property, to get rid of the parentheses.

0.07x + 300 - 0.06x = 332

Combine the constants on the right by subtracting 300 from both sides.

0.07x - 0.06x = 32

Combine like terms on the left.

0.01x = 32

Solve for x by dividing both sides by 0.01.

x = 3200

5000 - 3200 = 1800

$3,200 was invested at 7% and $1,800 was invested at 6%.

 
Thanks. I new the answer I just couldn't figure out how to get there.
 
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