Need help finding the equation of a tangent line, please.

[haley2011]

Find the equation of the tangent line to g(x)=square root 2x+9 at the point where x=0. Give answer in slope-intercept form.

I have g(x)=(2x+9)^1/2
g'(x)=1/2(2x+9)^-1/2
=1 over (2x+9)^1/2

I don't know where to go from there.

 

[Deleted member 4993]

Find the equation of the tangent line to g(x)=square root 2x+9 at the point where x=0. Give answer in slope-intercept form.

I have g(x)=(2x+9)^1/2
g'(x)=1/2(2x+9)^-1/2
=1 over (2x+9)^1/2

I don't know where to go from there.

What is the slope of the tangent line?

What is the point of tangency (i.e. the point where the tangent touches the curve)?

What is the equation of a straight-line when you know the slope and a point on the line?