Find the derivative \frac{d}{dt}\int_{0}^{sin(t)}\frac{1}{25-u^{2}} du
J John45 New member Joined Sep 15, 2010 Messages 22 Dec 23, 2010 #1 Find the derivative \(\displaystyle \frac{d}{dt}\int_{0}^{sin(t)}\frac{1}{25-u^{2}} du\)
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Dec 23, 2010 #2 Use : \(\displaystyle \frac{d}{dt}\int_{a}^{g(t)}f(u)du=f(g(t))g'(t)\)
