Find the derivative \frac{d}{dt}\int_{0}^{sin(t)}\frac{1}{25-u^{2}} du
J John45 New member Joined Sep 15, 2010 Messages 22 Dec 23, 2010 #1 Find the derivative ddt∫0sin(t)125−u2du\displaystyle \frac{d}{dt}\int_{0}^{sin(t)}\frac{1}{25-u^{2}} dudtd∫0sin(t)25−u21du
Find the derivative ddt∫0sin(t)125−u2du\displaystyle \frac{d}{dt}\int_{0}^{sin(t)}\frac{1}{25-u^{2}} dudtd∫0sin(t)25−u21du
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Dec 23, 2010 #2 Use : ddt∫ag(t)f(u)du=f(g(t))g′(t)\displaystyle \frac{d}{dt}\int_{a}^{g(t)}f(u)du=f(g(t))g'(t)dtd∫ag(t)f(u)du=f(g(t))g′(t)
Use : ddt∫ag(t)f(u)du=f(g(t))g′(t)\displaystyle \frac{d}{dt}\int_{a}^{g(t)}f(u)du=f(g(t))g'(t)dtd∫ag(t)f(u)du=f(g(t))g′(t)
