Okay so
[-Pi/2 , Pi/2] (cos2X +cosXsinX -3sinX^5)
so it got the anti derivatives of the first two terms
cos2X = .5sin(X)
cosXsinX = -.5sin^2 (X)
but i have no idea how to get the integral of -3sinX^5
anyways my final answer was 0 because I assumed that -3sinX^5 would be evaluated to 0
any help on answering this would be greatly appreciated
[-Pi/2 , Pi/2] (cos2X +cosXsinX -3sinX^5)
so it got the anti derivatives of the first two terms
cos2X = .5sin(X)
cosXsinX = -.5sin^2 (X)
but i have no idea how to get the integral of -3sinX^5
anyways my final answer was 0 because I assumed that -3sinX^5 would be evaluated to 0
any help on answering this would be greatly appreciated