Need a hint on how to set this one up...

[hank]

Find the area f the region enclosed by the graphs of
y = 1 / sqrt(1-9x^2), y = 0, x = 0, x = 1/6.

Just need a hint as I'm not sure how to set this guy up.

Thx!

 

[stapel]

You've drawn this, right...? So you can see what intersects where, and have figured out which is the "upper" edge, which is the "lower" edge, and where the limits of integration are...?

What have you gotten so far? Please be specific, starting with what you concluded from your graph. Thank you.

Eliz.

 

[skeeter]

Find the area f the region enclosed by the graphs of
y = 1 / sqrt(1-9x^2), y = 0, x = 0, x = 1/6.

\(\displaystyle \L A = \int_0^{\frac{1}{6}} \frac{1}{\sqrt{1 - (3x)^2}} dx\)

looks like the antiderivative will involve the arcsin function.