need a clarification

spacewater

Junior Member
Joined
Jul 10, 2009
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67
\(\displaystyle (-\frac{1}{64})^\frac{-1}{3}\)

When there is a negative exponent for a fraction you flip it the other way around to make it
\(\displaystyle (-\frac{64}{1})^\frac{1}{3}\)

I need a clarification whether this is the proper way to do it or not
 
\(\displaystyle (\frac{2}{5})^{-3}=\frac{1}{(\frac{2}{5})^3}=\frac{1\cdot (\frac{5}{2})^3}{(\frac{2}{5})^3\cdot(\frac{5}{2})^3}=\frac{(\frac{5}{2})^3}{1}=(\frac{5}{2})^3\)
 
Use what Loren showed you as a rule: (x/y)^(-p) = (y/x)^p
 
spacewater said:
\(\displaystyle (-\frac{1}{64})^\frac{-1}{3}\)

When there is a negative exponent for a fraction you flip it the other way around to make it
\(\displaystyle (-\frac{64}{1})^\frac{1}{3}\)

I need a clarification whether this is the proper way to do it or not


\(\displaystyle ^3\sqrt{-64} = - 4\)
 
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