Need a bit of help: Sin[theta] is rational iif theta=30 deg.

daon

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Jan 27, 2006
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This one has got me scratching my head. Showing that if \(\displaystyle \theta\) = 30, then \(\displaystyle Sin\theta\) is rational is obvious, but how to show that If \(\displaystyle Sin \theta\) is rational then \(\displaystyle \theta\) =30 is not (to me, anyway).

Ideas:

Should I start with \(\displaystyle Sin \theta \,\, = \frac{a}{b}\) for a,b in Z, and attempt to get a=1, b=2, so that I can say theta=30 deg?

Or would contradiction be the right route here?

-Daon
 
Please reread your posting.
Is that really what you mean to be saying?
If so, what are the conditions on theta?
I am not sure that you really mean what you wrote.
 
DOH! I forgot to mention that theta is rational and between 0 and pi/2, exclusive. Sorry, I've been reading math all day, and I'm really worn down!
 
Can you give us some clues from what you might have been studying?
What topics? What context does the from?
 
We have just finnished going over the existance of irrational numbers and proving things such as \(\displaystyle \sqrt{2} \,\, \notin \,\, \L \mathbb{Q}\), the Archimedean Property, 1/n principle. We assume to know all "high-school algebra" properties of the real numbers.

I hope thats enough information. Thanks.
 
Sorry that I could not answer before this.
The only way that I have ever seen is with continued fractions:
http://mathworld.wolfram.com/Sine.html (scroll well down the page).

I spent some time to see if I could do it with power series, a topic I though you might be able to use. But I had no luck. I would be interested to see what you were expected to do on this problem.
 
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