Natural Logs Functions

thelazyman

Junior Member
Joined
Jan 14, 2006
Messages
58
Dont really know how this equals to one, tried doing it didnt work out for me


y= e^ln(x)

Thanks
 
Did your pre-calculus algebra course not cover logarithms...? If not, I'm sure we can try to find some online lessons which will cover the concepts sufficiently to explain why e<sup>ln(x)</sup> equals 1.

Please let us know. Thank you.

Eliz.
 
Here is a big hint: \(\displaystyle y = e^{\ln (x)} \quad \Rightarrow \quad y' = \frac{{e^{\ln (x)} }}{x}\)
 
thelazyman said:
Please someone just answer it
So the other tutors (who aren't answering you any more) were correct? You just want a listing of the answers?

Okay: I'll start by assuming you've typoed the exercise, and that you're actually supposed to say why the function is the same as "y = x". The answer is:

. . . . . e<sup>ln(x)</sup> = x "by nature of logarithms and their bases."

Eliz.
 
I think you mean y' = 1.

Another Hint: \(\displaystyle f(f^{-1}(x)) = x\)
 
Top