natural log inequality

[WATIII]

812,555 * e^(x*0.0068) < 669,053 * e^(x*0.0127)

solve for x

 

[tkhunny]

Have you considered division?

 

[pka]

812,555 * e^(x*0.0068) < 669,053 * e^(x*0.0127)

solve for x

I think that you mean \(\displaystyle \Large 812,555 * e^{x*0.0068} < 669,053 * e^{x*0.0127}\)
Is that correct?

 

[WATIII]

Yes

 

[JeffM]

I am not even sure what the question is. It seems too straight forward.

[MATH]812,555 * e^{x*0.0068} < 669,053 * e^{x*0.0127} \implies \dfrac{812,555}{669,053} < \dfrac{e^{0.0127x}}{e^{0.0068x}}.[/MATH]
Why is that so?

Now what happens if you take the natural log of both sides?