n, 4n....: if sum of 1st 5 terms is 2046, what is n?

Sarah2391

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n, 4n...

The first term in the sequence above is n, and each term after the first is 4 times the preceeding term. If the sum of the first 5 terms is 2,046,
what is the value of n ?

Here's what I have so far...let me know if I'm on the right track and how to proceed
n + 4n + 16n + 64n + 256n = 2,046
 
Re: n, 4n....

n+4n+16n+64n+256n=2046
n[1+4+16+64+256]=2046
n[341]=2046
n=2046/341
n=6 answer
Arthur
 
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