multivariable limit: lim cos[(x^3 - y^3)/(x^2 + y^2)]

cheffy

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Jan 10, 2007
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Find the limit of f(x,y) as (x,y) -> (0,0)

\(\displaystyle \
f(x,y) = \cos \left( {\frac{{x^3 - y^3 }}{{x^2 + y^2 }}} \right)
\\)

My intuition says that this DNE, but I don't know what path to plug in to prove it. (or my intuition is wrong) Thanks!
 
I disagree with your intuition:

Use parametric forms: \(\displaystyle x = r\cos (t),\;y = r\sin (t),\;r = \sqrt {x^2 + y^3 }\)

Then \(\displaystyle \frac{{x^3 - y^3 }}{{x^2 + y^2 }} = \frac{{r^3 \left[ {\cos ^3 (t) - \sin ^3 (t)} \right]}}{{r^2 }} = r\left[ {\cos ^3 (t) - \sin ^3 (t)} \right]\).
Thus \(\displaystyle (x,y) \to (0,0)\; \Rightarrow \;r \to 0\) so \(\displaystyle \frac{{x^3 - y^3 }}{{x^2 + y^2 }} = r\left[ {\cos ^3 (t) - \sin ^3 (t)} \right] \to 0\).

Now we get \(\displaystyle \cos (0) = 1\).

Is it possible that the problem is different from the one posted?
 
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