Evaluate the following integral: integral from 0 to 1 integral from x to 1 sin(y^2) dy dx
K kiddopop New member Joined Sep 14, 2009 Messages 25 Mar 24, 2010 #1 Evaluate the following integral: integral from 0 to 1 integral from x to 1 sin(y^2) dy dx
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Mar 24, 2010 #2 ∫01∫x1sin(y2)dydx = ∫01∫0ysin(y2)dxdy = 12−cos(1)2 =˙ .229848847066\displaystyle \int_{0}^{1}\int_{x}^{1}sin(y^{2})dydx \ = \ \int_{0}^{1}\int_{0}^{y}sin(y^{2})dxdy \ = \ \frac{1}{2}-\frac{cos(1)}{2} \ \dot= \ .229848847066∫01∫x1sin(y2)dydx = ∫01∫0ysin(y2)dxdy = 21−2cos(1) =˙ .229848847066
∫01∫x1sin(y2)dydx = ∫01∫0ysin(y2)dxdy = 12−cos(1)2 =˙ .229848847066\displaystyle \int_{0}^{1}\int_{x}^{1}sin(y^{2})dydx \ = \ \int_{0}^{1}\int_{0}^{y}sin(y^{2})dxdy \ = \ \frac{1}{2}-\frac{cos(1)}{2} \ \dot= \ .229848847066∫01∫x1sin(y2)dydx = ∫01∫0ysin(y2)dxdy = 21−2cos(1) =˙ .229848847066
K kiddopop New member Joined Sep 14, 2009 Messages 25 Mar 24, 2010 #3 how do you switch the integral from x to 1 to 0 to y?
K kiddopop New member Joined Sep 14, 2009 Messages 25 Mar 24, 2010 #4 oh wait. you switched it from dy dx to dx dy. i got it now.
