crappiefisher26
New member
- Joined
- Jul 23, 2006
- Messages
- 49
How did they get this?
. . .(2x^3 / 5y^2) * (10y / 3x^2)
. . .= (2x^3 * 10y) / (5y^2 * 3x^2)
. . .= 4x / 3y
. . .(2x^3 / 5y^2) * (10y / 3x^2)
. . .= (2x^3 * 10y) / (5y^2 * 3x^2)
. . .= 4x / 3y