for the question (3x-4)(4x+3) how am i supose to get the answer 12x^2-7x-12
P pepsi123 New member Joined Apr 2, 2008 Messages 1 Apr 2, 2008 #1 for the question (3x-4)(4x+3) how am i supose to get the answer 12x^2-7x-12
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Apr 2, 2008 #2 pepsi123 said: for the question (3x-4)(4x+3) how am i supose to get the answer 12x^2-7x-12 Click to expand... Think of (3x - 4) as ONE quantitity. Now, use the distributive property. Multiply each term in the second set of parentheses by that "one quantity" that is outside: (3x - 4)*4x + (3x - 4)*3 Now, use the distributive property again. Multiply each term inside the parentheses by the term which is outside: 3x*4x - 4*4x + 3x*3 - 4*3 Do the multiplications, and combine like terms.
pepsi123 said: for the question (3x-4)(4x+3) how am i supose to get the answer 12x^2-7x-12 Click to expand... Think of (3x - 4) as ONE quantitity. Now, use the distributive property. Multiply each term in the second set of parentheses by that "one quantity" that is outside: (3x - 4)*4x + (3x - 4)*3 Now, use the distributive property again. Multiply each term inside the parentheses by the term which is outside: 3x*4x - 4*4x + 3x*3 - 4*3 Do the multiplications, and combine like terms.
