1) (2x^3y^4)^2 (x^-4y^6)^0
(x^-4y^6)^0 anything to the power of zero becomes 1
(2x^3y^4)^2x1
(2x^3y^4) (2x^3y^4)x1
=4x^6y^8
2) 2x^-5y^3
=2y^3 over x^5
Are these problems done correctly?
==================
You're going to have to be more careful with spacing and parnetheses so we can understand the problem better. You should have written it more like this:
1) (2x^3 y^4)^2 (x^(-4) y^6)^0
= (2x^3 y^4)^2 * 1
= 4x^6 y^8
2) 2x^(-5) y^3
= 2y^3 / (x^5)
So, yes, you were correct. good work!
Steve
