multiplying by numerator over factor in denominator

xbyxeqwhat

New member
Joined
Apr 18, 2016
Messages
5
Hi. I'm working on fractions in square roots but I think there is a property of fractions that I'm not understanding. If I have 1/44 (under a radical in case it matters) and can find the factors 1/(2*2*11). And that turns into 1/4 * 1/11. I'm not sure what the process is for separating 1/11 and why it works. Does it only work if 1 is in the numerator?
 
... If I have 1/44 (under a radical in case it matters) and can find the factors 1/(2*2*11). And that turns into 1/4 * 1/11. I'm not sure what the process is for separating 1/11 and why it works.
It's a basic property of fractions and multiplication:

. . . . .\(\displaystyle \dfrac{a}{bc}\, =\, \dfrac{a}{b\, \cdot\, c}\, =\, \dfrac{a}{b}\, \cdot\, \dfrac{1}{c}\, =\, \dfrac{1}{b}\, \cdot\, \dfrac{a}{c}\)

;)
 
Top