Multiplication: Use the numbers 0, 1, 2, 4, 5, 6, 7, 8, 9 to...

[Kwhit]

Use the numbers 0, 1, 2, 4, 5, 6, 7, 8, 9 to make this multiplication equation true
_ _ _ _ x 3 = _ _ _ _ _

each number must be used once, find 3 solutions

so stuck :'-(

 

[lookagain]

Use the digits 0, 1, 2, 4, 5, 6, 7, 8, 9 to make this multiplication equation true
_ _ _ _ x 3 = _ _ _ _ _

each digit must be used once, find 3 solutions

so stuck :'-(

Kwhit, they are digits in this context.

 

[Kwhit]

Righto thanks, guess you can't answer the question then?

 

[amberzak]

Firstly, to know a number is divisible by 3, all the digits in the number should add up to 3, or a multiple of three. So write down all answers you can get that's in the three times table. In other words, what combination of 5 digits add to a multiple of three.

The first digit after the = sign must be a one or a two, because 30000 divided by 3 is 10000, far too many digits there.

The first number has to be a three or higher to get a five digit answer.

does this start you off? A bit of trial and error is in order I think.

 

[amberzak]

The other way to look at it is to lay it out like long multiplication:

????
3
------
?????

then you can go through a process of elimination.

if you google search nrich1129 there are some clues as to how to find the first one.

 

[Kwhit]

Denis

There are 5 solutions.

One stands alone.

In the other 4, digits 1,6,8,9 appear in the 4digit number.

THANK YOU DENIS!!​

 

[lookagain]

Righto thanks, guess you can't answer the question then?

Wrong, Kwhit. Never, ever, make presumptions that someone can't answer your question, because your terminology was corrected. That's quite illogical of you to state that. Don't go down that road again. You stated that you were "so stuck?" I contend that you were "so lazy" as to not produce any work/ideas in this thread toward the solution.