[MOVED] solving 3a^2 + (4a)(18/a^2) = 3

Math wiz ya rite 09

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Aug 27, 2006
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I need help solving this equation:

3a^2 + (4a)(18/a^2) = 3

I know there are 3 answers, One real and two complex. The real one is -3. What are the complex ones?

Thanks,
Daniel
 
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Math wiz ya rite 09 said:
I need help solving this equation:
3a^2 + (4a)(18/a^2) = 3
I know there are 3 answers, One real and two complex. The real one is -3. What are the complex ones?

Your equation simplifes to: a^3 - a + 24 = 0 (I assume you did that)

Since a = -3, then (a + 3)(expression) = a^3 - a + 24
expression = (a^3 - a + 24) / (a + 3)

Perform long division to get expression = a^2 - 3a + 8

Can you finish?
 
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