[MOVED] show that csc x tan x = sec x, sec x cot x = csc x

[Sham]

show that
csc x tan x = sec x

and show that
sec x cot x = csc x


WHAT IS THIS....?

 

[stapel]

I'm sorry, but I don't understand your question. "This" is trigonometry, and you appear to be needing to prove two identities. Was none of this covered in class...?

A good start might be to convert the left-hand sides to sines and cosines, and see what you can get from that.

Eliz.

 

[soroban]

Re: hi guys

Hello, Sham!

Do you know any of the basic identities?

. . \(\displaystyle \cos x\,=\,\frac{1}{\sec x}\;\;\;\sec x \,=\,\frac{1}{\cos x}\)

. . \(\displaystyle \sin x \,=\,\frac{1}{\csc x}\;\;\;\csc x\,=\,\frac{1}{\sin x}\)

. . \(\displaystyle \tan x\,=\,\frac{\sin x}{\cos x}\;\;\;\cot x\,=\,\frac{\cos x}{\sin x}\)

Show that: \(\displaystyle \,\csc x\,\cdot\,\tan x \:= \:\sec x\)

We have: \(\displaystyle \:\csc x\,\cdot\,\tan x \:=\:\frac{1}{\sout{\sin x}}\,\cdot\frac{\sout{\sin x}}{\cos x} \;=\;\frac{1}{\cos x} \;=\;\sec x\)

Now try the second one . . .

 

[Sham]

thanks soroban it looks much easier to do when you have the rules

for the second one it is
1/cos x * cos x/sin x = cross out cosx = 1/sin x = csc x

THANK YOU