[MOVED] region of a system: picking point in region

Navyguy

Junior Member
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Jul 24, 2006
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Select the point which is in the feasible region of the system of inequalities.

. . .2x + 3y < 8
. . .5x + 2y < 7
. . .x > 0
. . .y > 0

. . .a. (1, 2)
. . .b. (1, 1)
. . .c. (0, 3)
. . .d. (3, 2)

My answer, after using Excel and a TI-84 calculator, is (3,2) from the list of possible answers. Thanks for looking over my answer.
 
Hello, Navyguy!

Select the point which is in the feasible region of the system of inequalities.

    2x+3y8,    5x+2y7,    x0,    y0\displaystyle \;\;2x\,+\,3y\:\leq\:8,\;\;5x\,+\,2y\:\leq\:7,\;\;x\:\geq\:0,\;\;y\:\geq\:0

a.  (1,2)      b.  (1,  1)      c.  (0,3)      d.  (3,2)\displaystyle a.\;(1,\,2)\;\;\;b.\;(1,\;1)\;\;\;c.\;(0,\,3)\;\;\;d.\;(3,\,2)

Hey, come on! . . . You need a calculator/computer to answer this one ??


Does a)  (1,2)\displaystyle a)\;(1,2) satisfy the inequalities?
It says: x=1,  y=2\displaystyle x\,=\,1,\;y\,=\,2 . . . plug them in!

    2(1)+3(2)8\displaystyle \;\;2(1)\,+\,3(2)\:\leq\:8 . . . Is this true?
    \displaystyle \;\; We have: 2+68\displaystyle \,2\,+\,6\:\leq\:8 . . . yes

    5(2)+2(1)7\displaystyle \;\;5(2)\,+\,2(1)\:\leq\:7 . . . Is this true?
    \displaystyle \;\;We have: 10+27\displaystyle \,10\,+\,2\:\leq\:7 . . . NO!

Therefore, a)  (1,2)\displaystyle a)\;(1,2) is not in the region.


Now test the other three points . . .

 
This is hard for some

Yes I'm trying to hard I think, This is hard for some and easy for others. Thanks for showing me ths easy way of putting the problem together. This is what I needed. thanks again.
 
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