Okay so i have a quiz tomorrow and i am still usure on how to use the three tests for symmetry for this following equaition:
Show three tests for symmetry
r = 2 – 2cosθ
I can pretty much graph it but cant find its tests for symmetry which are polar axis, θ = Pi/2, and pole.
Any suggestions will be very much appreciated.
Edit:
Okay so i tried reading my notes once again and so far i got this...but i am not so sure if its right...
Polar Axis:
r = 2 – 2cosθ
r = 2 – 2cos(-θ)
r = 2 – 2cosθ <---- Pass?
θ=π/2
r = 2 – 2cosθ(π-θ)
r = 2 – 2cosθ(cosπcosθ + sinπsinθ)
r = 2 - 2(-cosθ)
= 2+2cosθ <-------Fail
Pole
r = 2 – 2cosθ
-r = 2 – 2cosθ
r = -2 – 2cosθ <---- Fail
Is this how you do it?
Show three tests for symmetry
r = 2 – 2cosθ
I can pretty much graph it but cant find its tests for symmetry which are polar axis, θ = Pi/2, and pole.
Any suggestions will be very much appreciated.
Edit:
Okay so i tried reading my notes once again and so far i got this...but i am not so sure if its right...
Polar Axis:
r = 2 – 2cosθ
r = 2 – 2cos(-θ)
r = 2 – 2cosθ <---- Pass?
θ=π/2
r = 2 – 2cosθ(π-θ)
r = 2 – 2cosθ(cosπcosθ + sinπsinθ)
r = 2 - 2(-cosθ)
= 2+2cosθ <-------Fail
Pole
r = 2 – 2cosθ
-r = 2 – 2cosθ
r = -2 – 2cosθ <---- Fail
Is this how you do it?