[MOVED] please check soln to 'log5(x-4)= log7x solve for x'

[hope4ever]

log5(x-4)= log7x solve for x

These are just base 10 logs.
log100 = 2
This equation has the same format as log 40 = log (2x20)

Since both sides have log base 10, you divide by log base 10 and end up with 5(x-4) = 7x, so 5x -20 =7x x=-10

 

[galactus]

Do you have?:

\(\displaystyle \L\\log[5(x-4)]=log[7x]\)

\(\displaystyle \L\\5(x-4)=7x\)

\(\displaystyle \L\\5x-20=7x\)

\(\displaystyle \L\\-20=2x\)

\(\displaystyle \L\\x=-10\)

In that event, you're okey-dokey.