[MOVED] mileage making rental B a better bargain

[rosemarievip]

Car rental agency A will rent a compact car for $35 per day and an additional charge of $0.24 per mile. Car rental agency B will charge only $0.16 per mile but charges $41 per day. If Adam wanted to rent a car for three days, how many miles would Adam have to drive to make car rental agency B a better bargain?

 

[stapel]

Car rental agency A will rent a compact car for $35 per day and an additional charge of $0.24 per mile. Car rental agency B will charge only $0.16 per mile but charges $41 per day. If Adam wanted to rent a car for three days, how many miles would Adam have to drive to make car rental agency B a better bargain?

What have you tried? How far did you get? Where are you stuck?

Please reply showing your work and reasoning, starting with the variable you picked for the miles driven. Thank you!

Eliz.

 

[rosemarievip]

Please reply showing your work and reasoning, starting with the variable you picked for the miles driven. Thank you!

Eliz I am stuck with this problem, if you will tell me how to start I can probably finish it, Thanks rosemarievip.

 

[Deleted member 4993]

Car rental agency A will rent a compact car for $35 per day and an additional charge of $0.24 per mile. Car rental agency B will charge only $0.16 per mile but charges $41 per day. If Adam wanted to rent a car for three days, how many miles would Adam have to drive to make car rental agency B a better bargain?

Assume in three days, Adam will drive "d" miles - and both the rental company will charge equal.

So

How much would company A would charge to drive "d" miles in 3 days?.....................(1)

How much would company B would charge to drive "d" miles in 3 days?.....................(2)

equate (1) and (2) and solve for 'd'.

 

[rosemarievip]

Assume in three days, Adam will drive "d" miles - and both the rental company will charge equal. So

How much would company A would charge to drive "d" miles in 3 days?.....................(1)

How much would company B would charge to drive "d" miles in 3 days?.....................(2)

equate (1) and (2) and solve for 'd'.

35 * x / 0.24 = d
3 x 35 / 0.24 = d
105 / 0.24 = d 105 / 0.24 = 437.50 mi.

41 * x / 0.16 = d
3 x 41 / 0.16 = d
123 / 0.16 = 768.75 mi.

437.50 - 768.75 = 331.25 more miles

 

[Deleted member 4993]

It is incorrect.

However, I cannot understand any of the work you have shown.

Can you please explain what you are trying to accomplish in each line?

For example, what is 'x' in line '1' ? I presume you have used '*' for multiplication.

In line '2' - why are you dividing the daily charge of "A" (3 * 35 = 105) by the mileage charge ($ 0.24/mile)?