[MOVED] Graphing transformations

Louise Johnson

Junior Member
Joined
Jan 21, 2007
Messages
103
I have a graph with coordinates

Code:
+---+----+----+----+----+----+
| x | -2 | -1 |  0 |  2 |  4 |
+---+----+----+----+----+----+
| y |  0 | -2 |  0 |  2 |  0 |
+---+----+----+----+----+----+
What does it look like using these functions? (Just giving me the new coordinates would be great.)

1) 1 / f(x)

2) |f(x)| - 2
 
Louise Johnson said:
(Just giving me the new coordinates would be great.)
I'm sorry, but whoever told you that this was a place where you could post your homework and somebody would give you all the answers was mistaken.

Most (legitimate) tutors try to help students learn, so they can succeed on their own. There are places to which you can send your homework and receive back the completed assignment, but those charge money, and many (most?) are, at the least, quite sketchy. Caution is advised.

If you would like to learn how to complete this homework, please reply showing all of your work and reasoning so far, or, if you are unfamiliar with this topic, please specify that you are requesting links to lessons, so you can learn in time for the next test.

Thank you.

Eliz.
 
For #1 I had changed the function from 1/f(x) to (f(x))^-1 then come up with new coordinates of -2,0 -1,-0.5 0,0 2, 0.5 4,0

The transformation on the graph is an obvious extreme squishing

#2 |f(x)|-2 It seems like you should just move the graph lower by a value of two but also invert the one half upwards first.

new coordinates I got were -2,-2 -1,0 0,-2 2,0 4,-2

Any help would be appreciated
 
Louise Johnson said:
For #1 I had changed the function from 1/f(x) to (f(x))^-1 then come up with new coordinates of -2,0 -1,-0.5 0,0 2, 0.5 4,0

The transformation on the graph is an obvious extreme squishing

#2 |f(x)|-2 It seems like you should just move the graph lower by a value of two but also invert the one half upwards first.

new coordinates I got were -2,-2 -1,0 0,-2 2,0 4,-2

Any help would be appreciated
For #1, there is a problem when f(x) = 0. You've set 1/f(x) = 1/0 = 0, but actually division by zero is not defined. The values when f(x) != 0 are correct.

Your answer to #2 is correct.
 
JakeD, Thanks for your help. It may seem silly but I have spent a long time especially on this particular problem. transforming a graph with the following coordinates:

Code:
+---+----+----+----+----+----+
| x | -2 | -1 |  0 |  2 |  4 | 
+---+----+----+----+----+----+
| y |  0 | -2 |  0 |  2 |  0 | 
+---+----+----+----+----+----+
Using the function 1/f(x) I understand what you mentioned about dividing with zero and those coordinates being undifined. Would I simply state that as my answer for the problem? That the coordinates are undefined? When I did find some information regarding 1/f(x) it would only state that 1/f(x) is equal to or the same as (f(x))^-1 My real question is how can you graph it?

Thank you
Louise
 
Louise Johnson said:
JakeD, Thanks for your help. It may seem silly but I have spent a long time especially on this particular problem. transforming a graph with the following coordinates:

Code:
+---+----+----+----+----+----+
| x | -2 | -1 |  0 |  2 |  4 | 
+---+----+----+----+----+----+
| y |  0 | -2 |  0 |  2 |  0 | 
+---+----+----+----+----+----+
Using the function 1/f(x) I understand what you mentioned about dividing with zero and those coordinates being undifined. Would I simply state that as my answer for the problem? That the coordinates are undefined? When I did find some information regarding 1/f(x) it would only state that 1/f(x) is equal to or the same as (f(x))^-1 My real question is how can you graph it?

Thank you
Louise
I would state that 1/f(x) is undefined when f(x) = 0 and would not include any (x,y) coordinates on the graph for those x.

You're welcome
JakeD
 
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