The solution to the system of equations below is
x + 2y - z = -3
2x - y + 3z = 14
x + 4y - 2z = -8
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If you just want to check your answers, mine are: x = 2, y = -1, z = 3. (Of course, you could do that by substituting the values of the variables into the original equations to see if you get true statements.)
If you want to know how to do it, there are several methods:
combination of substitution and elimination
Cramer's Rule
matrix methods
I used the "rref" matrix technique ("reduced row echelon form") on the TI-83 calculator.
Steve
