[MOVED] find equation for horizontal translation of graph

kathy's

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Dec 20, 2005
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A horizontal translation is applied to the graph of y = X^3 + 2 so that it will pass through (3, 10). What is the new equation for the graph?

How do I do this?

Thank you! :)
 
Solve for \(\displaystyle A\) in \(\displaystyle y = (X-A)^3 + 2\), when \(\displaystyle X=3, y=10\).
 
get lost from here!

okay so

y=(x-A)^3+ 2

10= (3-A)^3 +2
10-2= (3-A)^3

8= (3-A)^3

now what?
 
Re: [MOVED] find equation for horizontal translation of grap

kathy's said:
A horizontal translation....
How do I do this?
You've received specific instructions for this particular exercise. In general, just use the translation rules they gave you:

. . . . .f(x ± a) is f(x) moved to the left or right "a" units

. . . . .f(x) ± a is f(x) moved up or down "a" units

Take f(x) = x<sup>3</sup> + 2, use the horizontal formula (above), and plug-n-chug to solve for "a".

Eliz.
 
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