[MOVED] factor 4x^3 - 11x^2 - 6x + 9 completely

[Laila]

Factor completely:

. . .4x^3 - 11x^2 - 6x + 9

I just don't know how to get started.

 

[pka]

The roots are: \(\displaystyle - 1,3,\frac{3}{4}.\)

 

[Laila]

The roots are: \(\displaystyle - 1,3,\frac{3}{4}.\)

How did you find that?

 

[pka]

One finds roots by factoring! RIGHT?
So if we know the roots the we know the factors. RIGHT?

 

[stapel]

Re: factoring 4x^3 - 11x^2 - 6x + 9 completely

i just dont know how to get started

I would suggest starting with the Rational Roots Test, and then applying synthetic division to the potential roots that the Test gives you.

If you get stuck in this process, or if you are supposed to use some other methodology, please reply showing all of your progress so far. Thank you.

Eliz.