[MOVED] convert 3 = 6y into logarithmic form

[runlemmingsrun]

Please convert the equation into logarithmic form:

3=6y

thanks

 

[tkhunny]

log(3) = log(6)+log(y)

Did you mean 3 = 6^y? So that log(3) = y*log(6)?

Or something else?

 

[runlemmingsrun]

log

if 3=6^y
can the solution be y=log6^3

 

[skeeter]

if \(\displaystyle \L 6^y = 3\)

then ...

\(\displaystyle \L \log_6{3} = y\)