flamathdummy
New member
- Joined
- Jun 1, 2005
- Messages
- 11
I have worked this....but I am not sure as how to write my final solution
3/x+2 > 2/x-1
3(x-1)/(x+2)(x-1) -2(x+2)/x-1(x+2) > 0
3x-3/(x+2)(x-1) - 2x+4/(x + 1) (x + 2) > 0
x-7/(x + 2)(x -1) > 0
So is my final solution x-7/(x+2)(x-1) ???
<--(-5)--(-4)--(-3)--((-2)--(-1)--(0))--(1)--(2)--(3)--(4)--(5)--(6)--((7)-->)
3/x+2 > 2/x-1
3(x-1)/(x+2)(x-1) -2(x+2)/x-1(x+2) > 0
3x-3/(x+2)(x-1) - 2x+4/(x + 1) (x + 2) > 0
x-7/(x + 2)(x -1) > 0
So is my final solution x-7/(x+2)(x-1) ???
<--(-5)--(-4)--(-3)--((-2)--(-1)--(0))--(1)--(2)--(3)--(4)--(5)--(6)--((7)-->)