MORE FACTORING BY GROUPING HELP PLEASE!!

[PreAlgebraDummy15]

ok I'm working on this one, am I finished?:

8a³ -12a² + 6a-9

(8a³-12a² +6a-9

4a (2a ²-3a1) + 3 (2a-3)

Edit: TKHunny - Edit your profile and turn on HTML.

 

[Denis]

ok I'm working on this one, am I finished?:

8a³ -12a² + 6a-9

(8a³-12a² +6a-9

4a (2a ²-3a1) + 3 (2a-3)

NO, you're not finished.
Take 4a^2 instead of 4a : what do you get?

 

[Guest]

just add 4a cubed instead of 4a like denis said and you'll be done