Hiya guys, newbie here. I'm really stuck on the following question, so I'd be grateful for any help.
Question:
Let \(\displaystyle x_0 \in R\) and \(\displaystyle \delta>0\). Prove that \(\displaystyle (x_0 - \delta, x_0 + \delta) = \{ x \in R : mod({x-x_0}) < \delta \}\).
My thinking:
I would show working, but I have nothing on my paper I was thinking of squaring \(\displaystyle mod ({x-x_0})\) to get \(\displaystyle +/- (x^2 + (x_0)^2 - 2xx_0) < \delta^2\) but got nowhere. Please help By the way, sorry, I couldn't get the I I mod signs up, so I just typed out mod. I hope you don't confuse this with modulo. My apologies.
Thanks,
Jenny x
Question:
Let \(\displaystyle x_0 \in R\) and \(\displaystyle \delta>0\). Prove that \(\displaystyle (x_0 - \delta, x_0 + \delta) = \{ x \in R : mod({x-x_0}) < \delta \}\).
My thinking:
I would show working, but I have nothing on my paper I was thinking of squaring \(\displaystyle mod ({x-x_0})\) to get \(\displaystyle +/- (x^2 + (x_0)^2 - 2xx_0) < \delta^2\) but got nowhere. Please help By the way, sorry, I couldn't get the I I mod signs up, so I just typed out mod. I hope you don't confuse this with modulo. My apologies.
Thanks,
Jenny x