Modifying formula to be expressed as a linear relationship

Confused_Idiot

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Joined
Nov 9, 2014
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Not sure if this is the correct section to post this on so sorry in advance.

This is the question I have:

Q = aHn

H
0.2
0.3
0.4
0.5
0.6
0.7
Q
0.0261
0.072
0.148
0.258
0.407
0.599




A) Show, using the Laws of Logarithms, how this formula can be modified in order to be expressed as a linear relationship

Unfortunately I don't even know where to begin on this, I looked around online but was unable to find anything relevant. I need to convert the formula in order to plot a straight line graph for part B though I should be able to manage that part.

Any help would be greatly appreciated.
 
What they are saying is that if a relationship is of the form \(\displaystyle Q= aH^n\) then taking the logarithm of both sides, \(\displaystyle ln(Q)= nln(H)+ ln(a)\), a linear relationship between x and y.

If you were to graph, not the data given, but ln(Q) and ln(H), you should get a straight line from which you can read off ln(a), the "y-intercept" and n, the "slope", and so get a and n.
 
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