Can someone please check if the below solutions are correct and if not tell me what I am doing wrong. Thanks in advance.
Question #1
How many ounces of a Silver Alloy that cost $6 per ounce must be mixed with
10 oz of Silver Alloy that cost $8 per ounce to make a mixture that cost $6.50 per ounces?
Solution: 6x + 8(10) = 6.50(10 + x)
6x + 80 = 65 + 6.50x
= 80 - 65 = 6.50x - 6x
= 15 = 0.5
= 15/0.5x = 0.5x/0.5x
x = 30
Question #2
How many gallons of a 15% acid solution must be mixed with 5 gal. of a 20% acid solution to make a 16% acid solution?
Solution: .15x + 1 = .16(16+x)
.15x + 1 = 2.56 + .16x
.15x - .16x = 2.56 - 1
-0.01x = 1.56
-0.01x/-0.01 = 1.56/-0.01x
x = -156
Question #3
How many ounces of pure chocolate must be added to 150 oz of chocolate topping that is 50% chocolate to make a topping that is 75% chocolate?
Solution: 75 = 0.75(150 + x)
75 = 112.5 + 0.75x
0.75x = 112.5 - 75
0.75x = 37.5
0.75x / 0.75x = 37.5 / 0.75x
x = 50
Question #1
How many ounces of a Silver Alloy that cost $6 per ounce must be mixed with
10 oz of Silver Alloy that cost $8 per ounce to make a mixture that cost $6.50 per ounces?
Solution: 6x + 8(10) = 6.50(10 + x)
6x + 80 = 65 + 6.50x
= 80 - 65 = 6.50x - 6x
= 15 = 0.5
= 15/0.5x = 0.5x/0.5x
x = 30
Question #2
How many gallons of a 15% acid solution must be mixed with 5 gal. of a 20% acid solution to make a 16% acid solution?
Solution: .15x + 1 = .16(16+x)
.15x + 1 = 2.56 + .16x
.15x - .16x = 2.56 - 1
-0.01x = 1.56
-0.01x/-0.01 = 1.56/-0.01x
x = -156
Question #3
How many ounces of pure chocolate must be added to 150 oz of chocolate topping that is 50% chocolate to make a topping that is 75% chocolate?
Solution: 75 = 0.75(150 + x)
75 = 112.5 + 0.75x
0.75x = 112.5 - 75
0.75x = 37.5
0.75x / 0.75x = 37.5 / 0.75x
x = 50