Mistake in question?

swag312

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Jan 9, 2020
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Hello, so there's a graph provided in the task which I'm trying to solve for a quite a while and I am really confused where the 5 to 8 line came from, because (5x+8y<5) doesn't create that sort of line. Is it possible that there's a misstake done by my teacher or am I understanding something wrong?
 

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You are correct about the line. The region in which \(\displaystyle 5x+ 8y\le 5\) is bounded by \(\displaystyle 5x+ 8y= 5\). When y= 0 that is 5x= 5 so one point on the line is (1, 0). When x= 0, 8y= 5 so y= 5/8. Another point on the line is (0, 5/8). The line shown, going through (8, 0) and (0, 5), is y= (-5/8)x+ 5 which would be 5x+ 8y= 40. I suspect there was a typo and \(\displaystyle 5x+ 8y\le 40\) was intended.

On the other hand, you misspelled "mistake" twice!
 
You are correct about the line. The region in which \(\displaystyle 5x+ 8y\le 5\) is bounded by \(\displaystyle 5x+ 8y= 5\). When y= 0 that is 5x= 5 so one point on the line is (1, 0). When x= 0, 8y= 5 so y= 5/8. Another point on the line is (0, 5/8). The line shown, going through (8, 0) and (0, 5), is y= (-5/8)x+ 5 which would be 5x+ 8y= 40. I suspect there was a typo and \(\displaystyle 5x+ 8y\le 40\) was intended.

On the other hand, you misspelled "mistake" twice!
Thank you so much, haha my english is not the best I know
 
Based on the graph the equation should have been 5x+8y < 40
 
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