missing something between 1/(-2y^2) = (x^3 + C)/3 and....

[lalala84]

hi, how do i go from this line:

1/(-2y^2) = (x^3 + C)/3

to:

(-2y^2) = 3/(x^3 + C)

it's more than just "flipping" each side, right?
what's the technical way of saying/doing it?

Thanks

 

[stapel]

it's more than just "flipping" each side, right?

I don't think so. I suppose one could think of it as cross-multiplying, followed by "cross-dividing", maybe....

what's the technical way of saying/doing it?

"Inverting both sides"...? "Taking the reciprocals"...?

Eliz.