aharvey said:This is pretty simple and straight forward, I am having some trouble figuring this out.
Find the missing exponent
(4x^5)?= 1
Its x to the fifth power by the way and the question mark is asking what is the missing exponent.
How can this be true?
Hey nice one, BigG; today is a good day, cause I learned something :wink:BigGlenntheHeavy said:\(\displaystyle 1^i \ = \ 1, \ i \ = \ \sqrt{-1}\)
\(\displaystyle Proof: \ Let \ 1^i \ = \ k, \ then \ i[ln(1)] \ = \ ln|k|, \ i(0) \ = \ ln|k|,\)
\(\displaystyle \implies \ln|k| \ = \ 0, \ k \ = \ e^0, \ k \ = \ 1, \ QED.\)
\(\displaystyle 1^x \ = \ 1, \ then \ the \ missing \ exponent \ x \ can \ be \ any \ number, \ real \ or \ imaginary.\)