Method for solving x in a division problem: 4x³ / 4x² - 4x + 1 = 0.675×10^-7

[Wandnmore]

Method for solving x in a division problem: 4x³ / 4x² - 4x + 1 = 0.675×10^-7

4x³ / 4x² - 4x + 1 = 0.675×10^-7 and x=0.00255621
I was half way through a chemistry question when I got stumped at this. I know up until that here it's completely correct, and as you see I have the answer, I just have no idea how to get there and I've tried a lot of things. I'd be very grateful if someone were to help! Thanks^^

 

[Deleted member 4993]

4x³ / 4x² - 4x + 1 = 0.675×10^-7 and x=0.00255621
I was half way through a chemistry question when I got stumped at this. I know up until that here it's completely correct, and as you see I have the answer, I just have no idea how to get there and I've tried a lot of things. I'd be very grateful if someone were to help! Thanks^^

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You neeed to apply grouping symbols (i.e.) brackets to post the problem correctly.

What you have posted, translates to:

\(\displaystyle \dfrac{4x^3}{4x^2} \ - \ 4x \ + \ 1 \ = \ 0.675 * 10^{-7}\)

I am sure you did not mean that!

Did you mean:

\(\displaystyle \dfrac{4x^3}{4x^2 \ - \ 4x \ + \ 1} \ = \ 0.675 * 10^{-7}\)

then you should have written it as:

4x³ / (4x² - 4x + 1) = 0.675×10^-7 and x=0.00255621

Have you been taught Newton's method of solving non-linear equations?

 

[Wandnmore]

.
You neeed to apply grouping symbols (i.e.) brackets to post the problem correctly.

What you have posted, translates to:

\(\displaystyle \dfrac{4x^3}{4x^2} \ - \ 4x \ + \ 1 \ = \ 0.675 * 10^{-7}\)

I am sure you did not mean that!

Did you mean:

\(\displaystyle \dfrac{4x^3}{4x^2 \ - \ 4x \ + \ 1} \ = \ 0.675 * 10^{-7}\)

then you should have written it as:

4x³ / (4x² - 4x + 1) = 0.675×10^-7 and x=0.00255621

Have you been taught Newton's method of solving non-linear equations?

You're right, apologies!
I have not been taught that, could you help?

 

[pka]

4x³ / 4x² - 4x + 1 = 0.675×10^-7 and x=0.00255621
I was half way through a chemistry question when I got stumped at this. I know up until that here it's completely correct, and as you see I have the answer, I just have no idea how to get there and I've tried a lot of things. I'd be very grateful if someone were to help! Thanks^^

Look if this is really a chemistry question, why are you worrying about mathematics?
Look at this. There is the answer. The tools to solve simple mathematics are so available on the web. My advise is "spend your time learning chemistry'.