Mean, standard deviation, standard error

[Violagirl]

In a recent GSS, the responses about the number of hours daily spent watching TV for the five subjects who identified themselves as Buddhists were

0, 5, 0, 1, 2

A) Find the mean, standard deviation, and standard error.

For the mean, I know you have to add each of the # of hours spent watching TV and divide by 5 to get a mean of 1.6 hours. For the standard deviation though, I am really confused as to how to find it for this problem. I know the formula for it and you that you need a probability proportion for part of it. However for this problem, none was given and so I am wondering if it is found from taking the number of hours that the subjects watch TV somehow? Outside of that, I know you can find the standard error after finding the standard deviation and dividing it by the sq. rt of 5 for this problem. Any help would be great!

 

[tkhunny]

You must get down to basics.

\(\displaystyle Mean = \frac{\sum x}{n}\)

\(\displaystyle SampleVariance = \frac{\sum (x^2) - \frac{\left[\sum x\right]^{2}}{n}}{n-1}\)

Plug'n Chug.

 

[Violagirl]

Ah ok so it is just the basic formulas then! The next part entailed constructing a 95% confidence interval for it. Thank you!