maximum of a polar equation

xxMsJojoxx

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I don't understand how we are able to find the maximum of this equation, without using a graphing calculation.
r = 2 + 5cos θ

I know to find the zeros, we substitute r for 0.
But how do we find the maximums?
 
I don't understand how we are able to find the maximum of this equation, without using a graphing calculation.
r = 2 + 5cos θ
I know to find the zeros, we substitute r for 0.
But how do we find the maximums?
First one must have some elementary knowledge of the cosine function such as:
1) the range is \(-1\le\cos(\theta)\le1\)
2) therefore, \(-5\le5\cos(\theta)\le 5\)
3) add two, \(-3\le2+5\cos(\theta)\le 7\).
From the above what is the maximum? Where (what \(\theta\)) causes the max?
 
I don't understand how we are able to find the maximum of this equation, without using a graphing calculation.
r = 2 + 5cos θ

I know to find the zeros, we substitute r for 0.
But how do we find the maximums?
Please state the entire problem exactly as given to you.

An equation doesn't have a "maximum"; a function does. But since this is the polar coordinate equation of a curve, it is not clear whether you want the maximum value of r (greatest distance from the origin) as you seem to be saying, or something else (the highest point on the curve?).
 
Please state the entire problem exactly as given to you.

An equation doesn't have a "maximum"; a function does. But since this is the polar coordinate equation of a curve, it is not clear whether you want the maximum value of r (greatest distance from the origin) as you seem to be saying, or something else (the highest point on the curve?).

1603846363820.png

I think it's asking for the greatest distance form the origin. I'm just wondering how I would find maximum |r| on a test. I think it's just the maximum on a standard cosine graph, which is 1, when I graph y=cos θ on a graphing calculator and restrict the domain -pi to pi. --- Is that right?
 
Good -- it is indeed just looking for the greatest value of |r|, which in this case corresponds to the maximum of r. And, yes, that is when [MATH]\cos(\theta) = 1[/MATH], as they say. You can figure that out from familiarity with the graph of the cosine, or with the unit circle (or with a calculator, though it's better not to need that).
 
pka said just what I would have written. Since you still do not seem to understand what he said I will say it again. Hopefully this time you will look closer.

r = 2 + 5cos θ
we know that -1< cos θ < 1
So -5< 5cos θ < 5
Then -3< 2+5cos θ < 7
0< |2+5cos θ| < 7
so |r| is 7.
 
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