maximum load

[logistic_guy]

here is the question

If the allowable bearing stress for the material under the supports at $\displaystyle A$ and $\displaystyle B$ is $\displaystyle (\sigma_b)_{allow} = 1.5$ MPa, determine the maximum load $\displaystyle P$ that can be applied to the beam. The bearing plates $\displaystyle A'$ and $\displaystyle B'$ have square cross sections of $\displaystyle 150$ mm $\displaystyle \times \ 150$ mm and $\displaystyle 250$ mm $\displaystyle \times \ 250$ mm, respectively.



my attemb
to solve this question, i need first to convert units to $\displaystyle SI$
i don't understand how $\displaystyle 150$ mm $\displaystyle \times \ 150$ mm $\displaystyle = 0.0225$ m$\displaystyle ^2$

 

[topsquark]

here is the question

If the allowable bearing stress for the material under the supports at $\displaystyle A$ and $\displaystyle B$ is $\displaystyle (\sigma_b)_{allow} = 1.5$ MPa, determine the maximum load $\displaystyle P$ that can be applied to the beam. The bearing plates $\displaystyle A'$ and $\displaystyle B'$ have square cross sections of $\displaystyle 150$ mm $\displaystyle \times \ 150$ mm and $\displaystyle 250$ mm $\displaystyle \times \ 250$ mm, respectively.

View attachment 38990

my attemb
to solve this question, i need first to convert units to $\displaystyle SI$
i don't understand how $\displaystyle 150$ mm $\displaystyle \times \ 150$ mm $\displaystyle = 0.0225$ m$\displaystyle ^2$

Basic unit conversions. Yet another review topic.

Convert 150 mm to m. Square that number.

-Dan

 

[logistic_guy]

Basic unit conversions. Yet another review topic.

Convert 150 mm to m. Square that number.

-Dan

that's simple?

$\displaystyle 150 \times mm \times \frac{m}{1000 \ mm} = 0.150 \ m$

$\displaystyle 0.150^2 \ m^2 = 0.0255 \ m^2$

it's confusing me when i work with two numbers in the same time
i can't believe i do it easily in this way