jessica87689
New member
- Joined
- Dec 2, 2008
- Messages
- 3
A 12 by 32 in rectangular piece of cardboard is used to construct and open box by cutting identical squares from each corner and then folding up the sides the size of the squares that must be removed to maximize the volume of the open box.
okay, ive gotten this far:
V= (12 -2x) (32 -2X) (X)
v= (384 -88x + 4X^2)x
V ' = (384x -088x^2 + 4x^3)
V ' = 4( 3x^2 - 44x+ 96 )
i know you need to find an optimization problem and then the restraints, but i dont know how to take this one any further.
okay, ive gotten this far:
V= (12 -2x) (32 -2X) (X)
v= (384 -88x + 4X^2)x
V ' = (384x -088x^2 + 4x^3)
V ' = 4( 3x^2 - 44x+ 96 )
i know you need to find an optimization problem and then the restraints, but i dont know how to take this one any further.