A =
B = (bij)3 x 4 , bij = i - j
Solve 2(BT A)T
I understand how to solve it, but I don't understand how B matrix is supposed to look like.
It might be something simple that I'm just overthinking, but I have no idea how Matrix B looks like.
My question is how does Matrix B look like. Thanks.
1 | 2 | 1 | 0 |
2 | 2 | 0 | 2 |
2 | 0 | 1 | 6 |
B = (bij)3 x 4 , bij = i - j
Solve 2(BT A)T
I understand how to solve it, but I don't understand how B matrix is supposed to look like.
It might be something simple that I'm just overthinking, but I have no idea how Matrix B looks like.
My question is how does Matrix B look like. Thanks.