Matrix Operations: Show A^2 = [[cos20 -sin20][sin20 cos0]]

maeveoneill

Junior Member
Joined
Sep 24, 2005
Messages
93
Let A=
[cos0 -sin0 ] *0= theta
[sin0 cos 0]

Show that A^2 =
[cos 20 -sin20]
[ sin 20 cos0]

When I figure out A^2 I get:
[cos 20 -sin20 cos0- sin 0 + cos0-sin0]
[sin0cos0 +sin0 cos0 -sin20 +cos 0 ]

How do I end up with
[cos 20 -sin20]
[ sin 20 cos0] instead?
 
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