S sampswan New member Joined Oct 20, 2016 Messages 1 Oct 20, 2016 #1 If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help.
If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help.
D Deleted member 4993 Guest Oct 20, 2016 #2 sampswan said: If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help. Click to expand... x/y=5/7 → x = 5/7 * y then: (3x-2y)/(4x-3y) → [3*5/7 * y - 2*y]/[4*5/7 * y - 3y] ...... simplify and continue....
sampswan said: If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help. Click to expand... x/y=5/7 → x = 5/7 * y then: (3x-2y)/(4x-3y) → [3*5/7 * y - 2*y]/[4*5/7 * y - 3y] ...... simplify and continue....
B Bob Brown MSEE Full Member Joined Oct 25, 2012 Messages 597 Oct 21, 2016 #3 Multiply both numerator and denominator by 1/y sampswan said: If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help. Click to expand... (3x-2y)/(4x-3y) = (3(x/y)-2) / (4(x/y)-3) when y is not zero which it is not. because (x/y)=5/7. Now just substitute 5/7 where you see (x/y).
Multiply both numerator and denominator by 1/y sampswan said: If x/y=5/7, find the value of (3x-2y)/(4x-3y). My fist post in this form. Thanks for any expert who could help. Click to expand... (3x-2y)/(4x-3y) = (3(x/y)-2) / (4(x/y)-3) when y is not zero which it is not. because (x/y)=5/7. Now just substitute 5/7 where you see (x/y).
