Math question

[Andric]

Somebody pls help

 

[Andric]

I reached to a equation that might not be helpful

 

[Dr.Peterson]

Try writing [MATH]f(x) = (x-\alpha)(x-\beta)[/MATH].

Also note that the limit can't be 3/5 unless f(a) = 0 (so that the limit is an indeterminate form), so suppose that [MATH]a = \alpha[/MATH] or [MATH]a = \beta[/MATH].

If you have any work, please show it, rather than just telling us that it exists. It may be important.

 

[pka]

\(\displaystyle f(x)=x^2+bx+c\)
\(\displaystyle \mathop {\lim }\limits_{x \to a} \frac{{f(x) - (x - a)}}{{f(x) + (x - a)}} = \frac{3}{5}\)
Then \(\displaystyle \alpha~\&~\beta\) are roots of \(\displaystyle f(x)=0\)

Above, I rewrote what Andic posted because like Prof Peterson I suspect that the limit is really incorrectly written.
In the limit is it \(\displaystyle a\text{ or }\alpha~?\)
Also note as roots we would have \(\displaystyle \alpha+\beta=-b~\&~\alpha\cdot\beta=c\)

 

[Andric]

Yea, I figured out right after I posted this question, thanks?