Hello, emmaiskool242!
Don't you ever LOOK at what you posted?
Haven't you caught on that your formatting is NOT preserved
\(\displaystyle \;\;\)and no one can read your problems?
And in algebra, we do NOT use "X" for multiplication!
m^2 m +n
__________ X _________
8m^2-8n^2 m^3 + m^2
We can only GUESS at what you meant . . .
I
assume the problem is: \(\displaystyle \L\:\frac{m^2}{8m^2\,-\,8n^2}\,\cdot\,\frac{m\,+\,n}{m^3\,+\,m^2}\)
Okay, one more time . . . FACTOR everything as much as possible.
And we have: \(\displaystyle \L\:\frac{m^2}{8(m\,-\,n)(m\,+\,n)}\,\cdot\frac{m\,+\,n}{m^2(m\,+\,1)}\)
Then reduce (cancel) as much as possible:
\(\displaystyle \L\:\frac{\sout{m^2}}{8(m\,-\,n)(\sout{m\,+\,n})}\,\cdot\frac{\sout{m\,+\,n}}{\sout{m^2}(m\,+\,1)} \;= \;\frac{1}{8(m\,-\,n)(m\,+\,1)}\)
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Don't try to make a "picture" of your problems.
They can be written "horizontally" like this:
(m^2)/(8m^2 - 8n^2) times (m + n)/(m^3 + m^2)
Enclose the numerators and denominators
in parentheses
Otherwise, you'll see something like : x - 2/y + y + 1/x - 3 \(\displaystyle \;\)
*
. . . and
who knows what the fractions are?
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*
Or worse: \(\displaystyle \;\)x-2/y+y+1/x-3
How come NO ONE uses spaces?
If your teacher wrote an exam problem like this: x+3/x-4+x-3/x+4
\(\displaystyle \;\;\)and you got it wrong, you'd complain . . . loudly.
IthinkI'llstartansweringquestionslikethis.