1/5(25x-1)-1/10(30x-5) ?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Feb 11, 2009 #2 tryangul said: 1/5(25x-1)-1/10(30x-5) ? Click to expand... Your formatting is unclear. Do you mean either of the following? . . . . .\(\displaystyle \frac{1}{5(25x\, -\, 1)}\, -\, \frac{1}{10(30x\, -\, 5)}\) . . . . .\(\displaystyle \frac{1}{5}(25x\, -\, 1)\, -\, \frac{1}{10}(30x\, -\, 5)\) What were the instructions for this? Are you supposed to simplify, evaluate, or something else? What have you tried? Where are you stuck? Please be complete. Thank you! Eliz.
tryangul said: 1/5(25x-1)-1/10(30x-5) ? Click to expand... Your formatting is unclear. Do you mean either of the following? . . . . .\(\displaystyle \frac{1}{5(25x\, -\, 1)}\, -\, \frac{1}{10(30x\, -\, 5)}\) . . . . .\(\displaystyle \frac{1}{5}(25x\, -\, 1)\, -\, \frac{1}{10}(30x\, -\, 5)\) What were the instructions for this? Are you supposed to simplify, evaluate, or something else? What have you tried? Where are you stuck? Please be complete. Thank you! Eliz.
F fasteddie65 Full Member Joined Nov 1, 2008 Messages 360 Feb 15, 2009 #3 tryangul said: 1/5(25x-1)-1/10(30x-5) ? Click to expand... I am fairly confident that the expression should be (1/5)(25x - 1) - (1/10)(30x - 5) = 5x - 1/5 - 3x + 1/2 = 2x + 3/10
tryangul said: 1/5(25x-1)-1/10(30x-5) ? Click to expand... I am fairly confident that the expression should be (1/5)(25x - 1) - (1/10)(30x - 5) = 5x - 1/5 - 3x + 1/2 = 2x + 3/10